There are 27 drops of a conducting fluid. each drop has radius r and each of them is charged to same potential $V_{1}$ they are then combined to form a bigger drop. the potential of the bigger drop is $V_{2}$ find the ratio $V_{2}/V_{1}$ ignore the change in density of fluid on combining the drops.

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let q be the charge on each drop : $V_{1}=rkqβ$Β Let R be radius of single drop. then $34βΟR_{3}=2734βΟr_{3}βR=3r$ $V_{2}=Rk(27q)β=3rk27qβ=9V_{1}βV_{1}V_{2}β=9$