A point charge is placed at the centre of a closed Gaussian spherical

surface of radius r. Electric flux passing through the surface is Φ. How is

the electric flux Φ through the surface affected when the following

changes are made in turn:

(i) The spherical surface is replaced by a cylindrical surface of the

same radius?

(ii) The point charge is replaced by an electric dipole? Justify your

answer in each case.

### Asked by shitikanthdas31 | 15th Jun, 2019, 09:58: AM

### (i) According to the guass law the flux through the closed surface is given by
The flux due to enclosed charge does not depend on the shape and size of the surface. Therefore the flux would remain same.
(ii)
In case of dipole, net charge inside the closed surface is zero. Hence flux will be zero.

### Answered by Utkarsh Lokhande | 15th Jun, 2019, 11:10: AM

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