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 Post subject: Arithmetic II; Q# 60, Pg. 76Posted: Mon May 02, 2011 6:23 pm

Joined: Mon Mar 14, 2011 5:08 am
Posts: 1
Hello can you please explain how to calculate this fraction problem?

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 Post subject: Re: Arithmetic II; Q# 60, Pg. 76Posted: Sat May 07, 2011 7:40 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
Numerator:
3 2/7 = 23/7

2 1/2 = 5/2

23/7 - 5/2 = 46/14 - 35/14 = 11/14

Denominator:
1/2 - 3/7 = 7/14 - 6/14 = 1/14

(11/14) / ( 1/14) = 11

-- Veritas Help

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