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 Post subject: Help-Math EssentialsPosted: Mon Dec 06, 2010 10:55 pm

Joined: Sun Nov 14, 2010 11:04 am
Posts: 10
Assistance with question 6,7, and 8 would be greatly appreciated. It appears as if these questions are the same format. If that is true an explanation of question 6 would be greatly appreciated.

Question six: When two-digit integer q is divided by 9, the remainder is 4. If q is a multiple of 7,
which of the following could be the units digit of q?

How do they arrive at 9 for the answer? I don't understand how 9 satisfies all conditions?

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 Post subject: Re: Help-Math Essentials #6Posted: Thu Dec 09, 2010 4:44 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
Bill,

two digit numbers that have a remainder of 4 when divided by 9:

13, 22, 31, 40, 49, 58, 67, 76, 85, 94

only 49 and 94 in the above list are multiples of 7. so only 9 and 4 could be possible units digits of q

-- Veritas Help

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 Post subject: Re: Help-Math EssentialsPosted: Tue Jan 18, 2011 5:26 pm

Joined: Sat Jan 01, 2011 2:47 pm
Posts: 3
you can formulate the words to math by this formula in any similar question,

q / 9 = x + 4 / 9

=> q = 9 x + 4

then start to substitute by x from 1 as there is no condition of x value.
when x = 1, q = 13
x = 2, q = 22
x = 3, q = 31 and so on,
until you find q is a multiple of 7 as it's a condition of q stated in the question
which is when x = 5, q = 49

4 and 9 are the possible answers,
4 is not included, so 9 is the correct answer.

Regards,

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