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 Post subject: Book VIII Data Sufficiency # 20 pg 44Posted: Wed Feb 23, 2011 12:06 am

Joined: Mon Mar 02, 2009 8:18 pm
Posts: 27
The back of the book says "the possible values of x are 1..9, but the only value of x that allows y to be an integer is x=5"

How did you know the only value of X = 5 so quickly without performing calculations? What is the trick to evaluating this so quickly?

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 Post subject: Re: Book VIII Data Sufficiency # 20 pg 44Posted: Wed Feb 23, 2011 6:37 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
x + y = 9

.52x + .58y = 4.92

52x + 58y = 492

26x + 29y = 246

y = (246 - 26x)/29 ... so we need 246 - 26x to be divisible 29

multiples of 29 are 29, 58, 87, 116 ...

-- Veritas Help

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