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 Post subject: Remainder problemPosted: Tue Mar 10, 2009 12:50 pm

Joined: Fri Mar 06, 2009 4:23 pm
Posts: 1
Hi, I need help with this question. I'm not very clear on this:

What is the remainder when positive integer x is divided by 6
1. When x is divided by 2 remainder is 1 ; When x is divided by 3 the remainder is 0
2. When x is divided by 12, remainder is 3

I understand that "1." describes that its a odd-number which is divisible by 3...but I'm unable to understand the rest.

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 Post subject: Re: Remainder problemPosted: Tue Mar 10, 2009 6:54 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
Hi,

Statement 2 tells us that, since dividing by 12 gives a remainder of 3, that the number, x, is 3, 15, 27, 39 ...

3/12 = 0, R3
15/12 = 1, R3
27/12= 2, R3

etc.

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