please explain the answer of the Q.No.17 from the advanced word problem which is the book XIV.


thanks
bandita

from (1)

y could be 91, 92, 93, 94, 95, 96, 97, 98, 98

but when any of these are divided into 33, the quotient is 0 with a remainder of 33

33/91 = 0, remainder 33

33/94 = 0, remainder 33

(do the long division to see this)


from (2) ... there are many prime numbers and many different possible remainders

with both (1) and (2) we would know that y is 97


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