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 Post subject: Geometry pg. 50 #20Posted: Fri Jun 17, 2011 9:37 pm

Joined: Thu Feb 10, 2011 11:12 pm
Posts: 10
Can you please explain/illustrate why the two statements together are not sufficient. I realized they were not sufficient individually, but I thought they were together.

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 Post subject: Re: Geometry pg. 50 #20Posted: Sat Jun 18, 2011 4:06 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
For rectangle R to be "silver" the ratio of its length to its width must be 2:1

There are many ways for rectangles to have the same area:

3 x 5, 15 x 1, 1/2 x 30, 1/4 x 60 , etc. (note that none of these are "silver")

2 x 4, 8 x 1, 16 x 1, etc. (note that some of these are "sliver" and some are not)

Comparing one side of another rectangle to one side of the "target" rectangle tells us nothing about the other side of the target rectangle.

R: 8 x 1
S: 4 x 2 ... the rectangles have the same area and one side of R (the 8) is double one side of S (the 4), but R is not silver

R: 4 x 2
S: 16 x 1/2 ... one side of R (the 2) is double one side of S (the 1/2), and R is silver

- Veritas Help

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 Post subject: Re: Geometry pg. 50 #20Posted: Thu Jun 23, 2011 10:15 pm

Joined: Thu Feb 10, 2011 11:12 pm
Posts: 10
Thanks for the response. I understand your first example and why info regarding one side doesn't necessarily help regarding the other. But in your second example, S with dimensions 16 x (1/2) wouldn't be silver since it's not 2:1.

Can you provide an example in which both R & S are silver, have the same area, and only 1 side of R has the ratio of 2:1 to S?

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 Post subject: Re: Geometry pg. 50 #20Posted: Sat Jun 25, 2011 6:46 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
In the second example, S could be 4x2

- Veritas Help

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