Answer explanation says "Since B cannot be ranked, there are 4 teams available to fill the other two spots: 4!/(4-2)! = 12. Multiple 12 x 3 to get 36 permutations that are not allowed"

I got to 12 but I don't know where the 3 comes from? Help plz.

There are 6*5*4 = 120 possible outcomes if we don't consider the requirement that B has to win a prize if A wins a prize.

We now have to "count" violations of the requirement:

if A is first, there are 4*3 = 12 ways for B to not be 2nd or 3rd
if A is second, there are 4*3 = 12 ways for B to not be 1st or 3rd
if A is third, there are 4*3 = 12 ways for B to not be 2nd or 1st

12 + 12 + 12 = 36

120 - 36 = 84


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