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 Post subject: Problem 24 Lesson 2:ArithmeticsPosted: Thu Aug 27, 2009 9:01 am

Joined: Tue Aug 25, 2009 2:16 pm
Posts: 9
It says that bus 2 goes from downtown to uptown in 2-2/3 that is equivalent to 2:40 so if the bus leaves at 8:40 it is supposed that arrives at 11:00. Is the answer ok?

Thank you,
Arturo

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 Post subject: Re: Problem 24 Lesson 2:ArithmeticsPosted: Thu Aug 27, 2009 4:42 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
Bus 1
7:50
9:02

Bus 2 -- 8 minute wait from 9:02
9:10
9:50

Bus3 -- 10 minute wait from 9:50
10:00

total wait time = 18 minutes

- Veritas Help

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 Post subject: Re: Problem 24 Lesson 2:ArithmeticsPosted: Thu Aug 27, 2009 11:27 pm

Joined: Tue Aug 25, 2009 2:16 pm
Posts: 9
What I don´t understand the first line in the chart. In Bus 2 How he passed from the time the bus leaved to the time it arrived. If it last for 2-2/3 hours. 2-2/3=120 min + 2*60/3=120min + 40min=2hours:40mins? In the answer bus 2 trajectory lasts 40 min?

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 Post subject: Re: Problem 24 Lesson 2:ArithmeticsPosted: Fri Aug 28, 2009 3:53 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
per the problem

he is on bus 1 for 1 1/5 hour (72 minutes)

and

he is on bus 2 for 2/3 hour (40 minutes)

-- Veritas Help

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