Welcome to the Veritas Prep online community! You can log in to begin posting messages, or register to create a new account.


Board index



Post new topic Reply to topic  Page 1 of 1
  [ 2 posts ] 
  Print view Previous topic | Next topic 
Author Message
leandro_jacomini@bmc.com
 Post subject: Algebra IV pag85 #62
PostPosted: Thu Nov 04, 2010 5:26 am 
Offline

Joined: Thu Sep 16, 2010 12:36 pm
Posts: 2
How can I imply that 1/2^x<0.01 is 2^x>100? Why the sign "<" was replaced by ">"?
I understand the reciprocal thing but I didn't understand the sign replacement. Can someone please help.
Thanks!
Top
 Profile  
 
VP_Help
 Post subject: Re: Algebra IV pag85 #62
PostPosted: Mon Nov 08, 2010 10:31 am 
Offline

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
1 / 2^x < 0.01
First, turn .01 into 1/100
1 / 2^x < 1/100
Then, multiply both sides by 2^x
1 < 2^x / 100
Then multiply both sides by 100
100 < 2^x
(now, if you need to, you can flip it around to say 2^x > 100, but we haven't changed anything in this process.)

Veritas Help
Top
 Profile  
 
Display posts from previous:  Sort by  
Post new topic Reply to topic  Page 1 of 1
  [ 2 posts ] 

Board index » Homework Support » Quant Questions » Problem Solving

All times are UTC - 8 hours [ DST ]

Who is online

Users browsing this forum: No registered users and 4 guests

You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
cron