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 Post subject: Question Math Essentials pg 102 #6Posted: Sun Oct 03, 2010 6:42 pm

Joined: Fri Sep 17, 2010 10:03 am
Posts: 5
The probem:

2^3 * 6^2/18 * 16^1/2

I think the solution is wrong! I got 2 as my answer How is the answer 4?

Also I asked a question on the first post that I made and no one replied back to my post! I am getting upset why, I never had a problem with other courses replying back to me! Please reply ASAP on the first post I created.

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 Post subject: Re: Question Math Essentials pg 102 #6Posted: Mon Oct 04, 2010 3:28 pm

Joined: Thu Jul 03, 2008 2:13 pm
Posts: 117
Hey LT,

No, that solution is correct. Here's how you'd break it down:

Numerator: 2^3 * 6^2 ---> 6^2 = 3^2 * 2^2, so you have:

Numerator: 2^3 * 2^2 * 3^2 =

Numerator: 2^5 * 3^2

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Denominator: 18 * 16^(1/2) ----> 18 = 2 * 3^2 and 16^(1/2) = 4 = 2^2, so you have:

Denominator: 2 * 2^2 * 3^2 =

Denominator: 2^3 * 3^2

_______________________________________________

Stacking numerator and denominator you have: (2^5 * 3^2) / (2^3 * 3^2)

The 3^2 terms cancel, leaving 2^5 / 2^3. That division leaves 2^2 = 4.

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