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 Post subject: arithmetic p. 74 #58Posted: Thu Sep 02, 2010 6:04 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
B/R = 5/7
7B = 5R
21B = 15R

(B + 3)/(R - 9) = 3/2
2B + 6 = 3R - 27
10B + 30 = 15R - 135

10B + 30 = 15R - 135
21B = 15R

-11B + 30 = -135
B = 15

R = 21

21 -9 = 12

-- Veritas Help

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 Post subject: Re: arithmetic p. 74 #58Posted: Sun Sep 12, 2010 1:19 pm

Joined: Wed Aug 18, 2010 3:37 pm
Posts: 2
Hi,

I understand how you set the equations up, but can you please explain why you multiplied 7B=5R by 3 and 2B + 6 = 3R - 27 by 5?

Also, I would appreciate it if you explain how the answer explanation on page 143 of the text is able to get 2y=12.

Thanks!

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 Post subject: Re: arithmetic p. 74 #58Posted: Sun Sep 12, 2010 6:05 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
It was so that we could have 15R in both of them -- Since we had 5R in one of them and 3R in another, we get them both to equal 15R so that we can then set both equations equal to each other.

Veritas Help

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