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p = old price n = old qty
(p + 1000)(n - 5) = 594000
and
(p)(n) = 594000 - 26000 = 568000 ... or p = 568000/n
pn -5p + 1000n - 5000 = 594000
pn - 5p + 1000n - 599000 = 0 .... substitute for p
568000 - 5*568000/n + 1000n - 599000 = 0
divide each term by 1000
568 - 5*568/n + n - 599 = 0
5*568/n + n - 31 = 0 ... mutilple each term by n
5*568 + n^2 - 31n = 0
n^2 - 31n + 5*568 = 0
try the answer choices (remember, we want the number sold at the new price, but we have defined "n" as the number sold at the old price)
so, if an answer choice is 71, put in 71+5 = 76 for n in the above.
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