Page 1 of 1 [ 2 posts ]
 Print view Previous topic | Next topic
Author Message
 Post subject: triangle problemPosted: Thu Jun 02, 2011 8:24 pm

Joined: Mon Feb 28, 2011 11:17 pm
Posts: 6
The perimeter of a certain isosceles right triangle is 16 + 16 * square root of 2. What is the length of the hypotenuse of the triangle?

A - 8
C - 4*sqrroot 2
D - 8*sqrroot 2
E - 16*sqrroot 2

I started the problem by knowing that 2x + x*sqrroot 2 = perimeter. It looks easy but I couldn't get the arithmetic to work out. I know that x is one of the small sides so I would have to do an extra step to find the length of the hypotenuse. Please let me know the steps for the arithmetic. Also, if there is a quicker way to get the answer it would be greatly appreciated.

Thank you,
Eric

Top

 Post subject: Re: triangle problemPosted: Sat Jun 04, 2011 9:18 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
Please send a screen copy of the problem to help@veritasprep.com

Top

 Display posts from previous: All posts1 day7 days2 weeks1 month3 months6 months1 year Sort by AuthorPost timeSubject AscendingDescending
 Page 1 of 1 [ 2 posts ]

 All times are UTC - 8 hours [ DST ]

#### Who is online

Users browsing this forum: No registered users and 2 guests

 You cannot post new topics in this forumYou cannot reply to topics in this forumYou cannot edit your posts in this forumYou cannot delete your posts in this forumYou cannot post attachments in this forum

 Search for: