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jmhopkin
 Post subject: quick question re: problem 49 p 140 Arithmetic book
PostPosted: Tue Apr 19, 2011 12:53 pm 
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Joined: Tue Apr 19, 2011 12:46 pm
Posts: 2
In the solution it says we have the algebraic problem x = (y/100)*z. I'm not sure why this is escaping me... but I don't see how how do we manipulate the problem to read z/x = 100/y as mentioned in the solution? Thanks!
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VP_Help
 Post subject: Re: quick question re: problem 49 p 140 Arithmetic book
PostPosted: Tue Apr 19, 2011 5:28 pm 
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Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
x = (y/100) * z, since y is a percentage

from (1)

z/x = 0.8

z = 0.8 * x

x = 1/(0.8) * z

so y/100 = (1/0.8)

y = 100/0.8


from (2)

x - (20/100)x = z

(80/100)x = z

x = (100/80)z

so y/100 = 100/80

y = 100/.8

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