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 Post subject: Quotient & RemainderPosted: Sun Jan 16, 2011 3:21 pm

Joined: Sun Jan 16, 2011 3:11 pm
Posts: 7
All,
I'm not sure if this question has been asked here already but someone did on this forum and I still don't get the explanation. Can someone help me out?

Here's the question:

If 13,333-n is divisible by 11, and 0<= n <= 11, what is n?

A: 1
B: 3
C: 5
D: 7
E: 9

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 Post subject: Re: Quotient & RemainderPosted: Mon Jan 17, 2011 3:53 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
They're telling us that one number between 13,333 and 13322 is divisible by 11. If we can figure out which one it is, we can find n.

Let's look first at 13333 --
When we divide this by 11, we get 1212 with a remainder of 1. This means that 13332 is divisible by 11.
(You can test this one if you want to)

Thus, since we know that 13,333-n is divisible by 11, and we know that 13,333-1 is divisible by 11, we know that n=1.

Make more sense?

Veritas Help

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 Post subject: Re: Quotient & RemainderPosted: Sat Jan 22, 2011 10:43 am

Joined: Sun Jan 16, 2011 3:11 pm
Posts: 7
Thanks VP_Help!

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