Post new topic Reply to topic  [ 2 posts ] 
Author Message
 Post subject: Arithmetic (Vol. II), Question #95.
PostPosted: Sat Oct 30, 2010 9:27 am 
Offline

Joined: Thu Jul 01, 2010 12:05 am
Posts: 35
The data sufficiency question asks the following: "How long did it take Betty to drive nonstop on a trip from her home to Denver, Colorado?"

(1) If Betty's average speed for the trip had been 1.5 times as fast, the trip would have taken 2 hours.

(2) Betty's average speed for the trip was 50 miles per hour.

The correct answer is A, because (3/2)r times (2/3)t = rt, and 2t/c = 2 :shock:. Could you explain how the first equation transformed into the second equation (i.e. 2t/c = 2)?


Top
 Profile  
 
 Post subject: Re: Arithmetic (Vol. II), Question #95.
PostPosted: Sat Oct 30, 2010 10:13 am 
Offline

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
If Betty's average speed for the trip had been 1.5 times as fast, the trip would have taken 2 hours

We know that for her actual trip, RT=D (where R is her actual rate, T is her actual time and D is her actual distance.)

Now, from the first statement, we know that if her rate had been 1.5R instead of R (1.5R = (3/2)R) then her time would have been 2 instead of T. Since we're dealing with the same trip, our D is still just D.

Here's what we get:
1.5R * 2 = D
3R/2 * 2 = D
3R = D

Since we know that RT=D AND that 3R=D, we know that RT = 3R. This tells us that T=3, and this is what they asked in the original question.

Veritas Help


Top
 Profile  
 
Display posts from previous:  Sort by  
Post new topic Reply to topic  [ 2 posts ] 

All times are UTC - 8 hours [ DST ]


Who is online

Users browsing this forum: No registered users and 5 guests


You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot post attachments in this forum

Search for:
cron