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 Post subject: Math Essentials pg 59 (question 6)Posted: Mon Jul 12, 2010 3:06 pm

Joined: Sun Jul 11, 2010 4:32 pm
Posts: 2
Hi,

I was wondering if there was a quick way to solve Question #6 on page 59 in the Math Essentials book?

Thanks,
Michelle

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Mon Jul 12, 2010 3:24 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
.00667/800 * 16000/6 (invert and multiply)

.00667/6 * 16000/800

667/10000 * 1/6 * 20

667/1000 * 1/100 * 1/6 * 20

2/3 * 1/100 * 1/6 * 20

2/3 * 1/5 * 1/6

-- Veritas Help

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Mon Jul 12, 2010 5:37 pm

Joined: Sun Jul 11, 2010 4:32 pm
Posts: 2
sorry, i'm still confused....isn't the question "what is the result if 0.00667/800 is divided by 0.025/3000?" so, where do you get 16000/6 from?

it also says, the answer is supposed to be 1.

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Mon Jul 12, 2010 6:08 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
We must have different editions of the text. Try using the approach that I illustrated on your version. Post it here and I will review it for you.

- Veritas Help

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Sun Nov 21, 2010 9:34 pm

Joined: Tue Nov 16, 2010 5:56 pm
Posts: 5
Is this the right approach for the following question?

Q:

0.00667 / 800 x 3000 / 0.025

A:

0.00667 / 0.025 x 3000 / 800

667.10^-5 / 5.5.10^-2 x 2.3.5.10^2 / 2.2.2.10^2

Then factorise out to arrive at:

3.667.10^-5 / 4.5.10^-3

giving (2001/20) x 10^-5-3

which equals 100.05 x 10^-2 = 1.0005

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Mon Nov 22, 2010 2:32 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
It does look as if you've approached it the correct way. (Hard to follow in a text-based format, as our notation choices are limited, but as far as I can tell, you've followed the right process.

Veritas Help

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Sun Dec 19, 2010 5:16 pm

Joined: Sun Nov 14, 2010 11:04 am
Posts: 10
I'm working on this problem as well. Can you explain how you arrived at 5.5. 10^-2. I'm assuming that this represents 0.025 in the original problem.

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 Post subject: Re: Math Essentials pg 59 (question 6)Posted: Mon Dec 20, 2010 9:17 am

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
I believe it might be a typo -
It's supposed to be 2.5 * 10^(-2)

Veritas Help

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