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 Post subject: Math essentials pg 59 # 3Posted: Wed Apr 04, 2012 3:21 pm

Joined: Sat Oct 01, 2011 5:29 pm
Posts: 2
I need help with this question.
I'm having a problem figuring out what to do when I have reduced the fractions and I'm trying to get the reciprocal of the 10^-7....

Here's how I worked the problem out:

900/.00005 x .25/.03 =

3x3 x10^2/ 5x10^5 multiplied by 5x5x 10^-2/3x 10^-2
after reducing I'm left with:
3x5 x10^2 (+)-2/ 10^-5-2

the issue I'm running into is when I add the positive 2 and negative 2, I'm left with 10^0,which should be 1.

I'm also not sure what to do with the 10^-7... I know I'm supposed to take the reciprocal and do the opposite sign... which would leave me with:

3x5 x 1 (the 1 comes from the 10^0) x 10^7/1= which would leave me with 150,000,000.

I know this is wrong based off the answer on the On demand guide...I just needhelp in figuring out where my logic is wrong.

Sarah

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 Post subject: Re: Math essentials pg 59 # 3Posted: Thu Apr 05, 2012 7:20 am

Joined: Sat Oct 01, 2011 5:29 pm
Posts: 2
Hello...???... Anybody there?

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 Post subject: Re: Math essentials pg 59 # 3Posted: Thu Apr 05, 2012 4:36 pm

Joined: Thu Feb 12, 2009 6:32 pm
Posts: 497
900/(5 * 10^(-5)) * .25/(3/100)

(900 * 10^5 * 100 * .25 ) /(5 * 3)

300 * 10^5 * 20 * .25

300 * 10^5 * 5

1500 * 10^5

15 * 10^2 * 10^5

15 * 10^7

- Veritas Help

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