Now that we have covered some variations that arise in inequalities in GMAT problems, let’s look at some questions to consolidate the learning.

We will first take up a relatively easy OG question and then a relatively tougher question which looks harder than it is because of the use of mods in the options (even though, we don’t really need to deal with the mods at all).

**Question 1:** Is n between 0 and 1?

Statement 1: n^2 is less than n

Statement 2: n^3 is greater than 0

**Solution:** Let’s take each statement at a time and see what it implies.

Statement 1: n^2 < n

n^2 – n < 0

n( n – 1) < 0

This is the required form of the expression. We can now put it on the number line.

For the expression to be negative, n should be between 0 and 1. So we can answer the question with a ‘yes’. Statement 1 alone is sufficient.

Statement 2: n^3 > 0

This only implies that n > 0 and we do not know whether it is less than 1 or not. Hence this statement alone is not sufficient.

Answer: (A)

This question could have been easily solved in a minute if you understand the theory we have been discussing for the past few weeks. Let’s go on to the trickier question now.

**Question 2:** Which of the following represents the complete range of x over which x^5 – 4x^7 < 0?

(A) 0 < |x| < ½

(B) |x| > ½

(C) –½ < x < 0 or ½ < x

(D) x < –½ or 0 < x < ½

(E) x < –½ or x > 0

**Solution:** As I said, it looks harder than it is. We can easily do this in a minute too. First, let’s look at the given inequality closely: x^5 – 4x^7 < 0

x^5 (1 – 4x^2) < 0 (taking x^5 common)

Just to make things easier right away, take out 4 common and multiply both sides by -1 to get

4(x^5)(x^2 – 1/4) > 0 (notice that the sign has flipped since we multiplied both sides by -1)

4(x^5)(x – ½)(x + ½) > 0

Think of the points you are going to plot: 0, 1/2 and -1/2. Recall that any positive odd power can be treated as a power of 1.

In which region is x positive? -1/2 < x < 0 or x > 1/2.

This is our option (C).

A quick word on the other options: What does 0 < |x| < ½ imply? It implies that distance of x from 0 is less than ½. So x lies between -1/2 and 1/2 (but x cannot be 0).

What does |x| > ½ imply? It implies that distance of x from 0 is more than ½. So x is either greater than ½ or less than -1/2.

If you are wondering what I am talking about, check out an old QWQW post: http://www.veritasprep.com/blog/2011/01/quarter-wit-quarter-wisdom-do-what-dumbledore-did/

We have discussed how to deal with modulus here. We hope this discussion has made such questions easier for you!

*Karishma, a Computer Engineer with a keen interest in alternative Mathematical approaches, has mentored students in the continents of Asia, Europe and North America. She teaches the **GMAT** for Veritas Prep and regularly participates in content development projects such as this blog!*

Could you perhaps explain this curve you keep drawing? Seen it on more than a couple of forum posts by you. Don’t quite get it…. :-(

I draw the curve to just separate out the regions clearly. We mark the rightmost region positive and then alternate the signs. If you want, you can skip making the curve.

This post is where the curve first appeared: http://www.veritasprep.com/blog/2012/06/quarter-wit-quarter-wisdom-inequalities-with-multiple-factors/

Dear Karishma,

if i get n-1<0 then should i take n1.

Your question is not very clear. Could you elaborate?

Dear Karishma,

if i get n-1<0 then should i take

n1

Karishma,

I didn’t get the range of x you found for 0 < |x| < ½

I found the range as : 0<x<1/2 or,

-1/2 <x< 0

How could the range be -1/2<x<1/2 as, at x=0 , distance of x from 0 is=0

Please clarify.

Yes, the range is -1/2 < x < 1/2 but x is not equal to 0. (I have put this in the post)

or as you say, 0 < x < 1/2 or -1/2 < x < 0

Thanks!

That helped .

Hi,

Would you please solve m^3 > m^2 using the same logic. It becomes m^2(m-1) > 0. If I apply the number line +/- logic, for some reason it fails. How do things change when there is a even power involved? Thanks a lot!

Check out this post. We have discussed how to handle this complication here.

http://www.veritasprep.com/blog/2012/07/quarter-wit-quarter-wisdom-inequalities-with-complications-part-ii/

this is awesome! thanks very much!