Two trains, A and B, traveling towards each other on parallel tracks, start simultaneously from opposite ends of a 250 mile route. A takes a total of 3 hours to reach the opposite end while B takes a total of 2 hours to reach the opposite end. When train A meets train B during the journey, how far is train A from its starting point?

This question is not difficult but when I give it to my students, I see long, winding solutions, solutions that I find difficult to follow and after looking at a couple, my head starts to spin. Though, admittedly, most of them have the correct answer at the end. But you see, the correct answer alone is not enough. I like to see correct answers along with intuitive, intellectually stimulating methods. The most satisfying is seeing a blank rough sheet and the correct answer together. Rather than relying on the scratch pads and the markers, try and rely on your beautiful minds!

Now, if you haven’t tried answering the above given question on your own yet, do it right away before reading the rest of the post.

So what kind of a solution do I like? The following:

Since A takes 3 hours to travel the same distance for which B takes 2 hours, time taken by A and B is in the ratio 3:2 so their speeds must be in the ratio 2:3. Hence, A will cover 2/5^{th} of the total distance of 250 miles and B will cover the rest of the (3/5)th of the total distance. Therefore, A will be 100 miles from its starting point when A and B meet.

How much time do you think it takes one to think this through? 20-30 seconds at most! It just sounds so simple, doesn’t it? But actually it involves a thorough understanding of quite a few fundamental concepts. If you take the time to get comfortable with these concepts, you will be able to save a lot of time on many Arithmetic questions. So let’s delve into some basics.

Ratios – One of the most basic and important concepts in the ‘just figure it out’ methodology.

A ratio gives a measure of the relation between two quantities. It doesn’t give either of the two quantities. So score of A : score of B = 4:5 means that for every 4 points A scored, B scored 5 points.(It doesn’t mean that A actually scored 4 and B actually scored 5.) To get the actual points scored by the two of them, we would need one of the following (or one of many other) scenarios:

Scenario 1:

Given: A scored 40 points. How many points did B score?

Obviously 50, right? If A scored 10 times 4, B must have scored 10 times 5, right?

Scenario 2:

Given: A and B together scored 90 points. How many points did A score and how many did B score?

If I think in ratio terms, A and B scored 4 and 5 respectively i.e. 9 in all. But actually, they scored 90 in all i.e. 10 times 9. So A must have scored 10 times 4 = 40 and B must have scored 10 times 5 = 50.

Scenario 3:

Given: B scored 10 points more than A. How many points did A score?

B:A is 5:4. For 4 points of A, B scored 1 extra. If B actually scored 10 points more than A, A must have scored 10 times 4 i.e. 40 points (and B must have scored 50 points)

In each of the cases above, you can think of 10 as the common multiplier. It helps you arrive at all the actual values. When you multiply the numbers in ratio terms with the multiplier, you get the actual values. Let us look at another example.

Weight of Adam : Weight of Sally = 7:5. Adam’s weight is 133 pounds. What is Sally’s weight?

The common multiplier is 19 (because 133/7 = 19). Hence, Sally’s weight is 5*19 = 95 pounds. The sum of their weights is (7+5)*19 = 228. The difference of their weights is (7-5)*19 = 38 pounds

Let us take an actual ratios question from our Arithmetic book now.

The ratio of Blue pens to Red pens is 5:7. When 3 Blue pens are added to the group and 9 Red pens are removed, the ratio of Blue pens to Red pens becomes 3:2. How many Red pens are there after the change?

(A) 3

(B) 5

(C) 9

(D) 12

(E) 18

Let us say the multiplier of 5:7 is x.

So there must have been 5x Blue pens and 7x Red pens before the change.

After the change, number of Blue pens = 5x + 3, number of Red pens = 7x – 9

The ratio of these numbers is 3:2 which can also be represented as 3/2.

(5x + 3)/(7x – 9) = 3/2

Solving this, we get x = 3

After the change, there are 7*3 – 9 = 12 Red pens

This is the basic framework of ratios. Its uses lie in solving not only ‘Ratio Questions’ but also ‘Weighted Average Questions’, ‘Distance Speed Time Questions’, ‘Work Rate Questions’ etc. The benefit of using ratios is that you can get rid of the necessity of making and solving equations in many cases. For examples and explanations, check out subsequent posts (that is where I will explain the solution of the trains question given above too).

*Karishma, a Computer Engineer with a keen interest in alternative Mathematical approaches, has mentored students in the continents of Asia, Europe and North America. She teaches the GMAT for Veritas Prep in Detroit, Michigan, and regularly participates in content development projects such as this blog!*

## 6 thoughts on “Quarter Wit, Quarter Wisdom: The Sorcery of Ratios”

Comments are closed.

thanks

Karishma,

This was a nice way to solve ratios problems intuitively!

How can we solve the following problem with the above method?

Let ratio A:B= 4:5

A+3 : B = 9:10

then, what is the value of A+B ?

I tried with the traditional method and found the multiplier= 6

However, unable to get it in the way you have suggested.

Please help.

Look at the last question in the post above.

A:B = 4:5

A = 4x, B = 5x

(4x + 3)/5x = 9/10

x = 6

A+ B = 9x = 54

In fact, you don’t even need to do this much since the values are pretty simple. A:B = 4:5 = 8:10 etc

Now if I add 1 to A when A and B are 8 and 10, I get 9:10. But I need to add 3 and get 9:10. So A and B must actually be 3 times 8 and 10 i.e. they must be 24 and 30.

This is a very intuitive approach and I suggest you to follow it only if you totally get it. Otherwise the one discussed above is better.

Thanks for all the help, Karishma!

Got it now !

so, you brought it till A+1 form to get the multiplier….

means, (A+1) / B = 9/10

(A+3)/ B = 9/10

i.e 3(A+1)/ 3B = 9/10 hence, A & B are multiples of 3 each.

Yes, i will follow your suggestion.

I learnt the graphical approach to inequalities from your posts and am doing good now after some practice.Hope, i will be able to apply these techniques while practising official questions.

I am having timing issues in the word translation problems.Hence, trying to learn ways to do the problems faster yet accurately.

I have posted a query(may sound silly :-) ) in the following url :

http://www.veritasprep.com/blog/2011/03/quarter-wit-quarter-wisdom-applications-of-ratios-in-tsd/

Please respond if possible.

Thanks again for these nice & helpful articles !

Hi Karishma,

I’m not able to find the subsequents posts for this topic.

Can you please help with the links?

Thanks!

It is here:

http://www.veritasprep.com/blog/2011/03/quarter-wit-quarter-wisdom-applications-of-ratios-in-tsd/